1. **Problem Statement:** Solve the equation and explain the solution process. 2. **Understanding the Problem:** The problem is to find the solution to the equation provided (though the exact equation is not visible in the input). 3. **General Approach:** - Identify the type of equation (linear, quadratic, polynomial, etc.). - Use appropriate algebraic methods such as factoring, quadratic formula, or substitution. 4. **Key Formulas and Rules:** - Quadratic formula: $$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ - Factoring: Express the polynomial as a product of simpler polynomials. - Zero product property: If $$ab=0$$ then $$a=0$$ or $$b=0$$. 5. **Step-by-Step Solution:** (Since the equation is not provided, here is a generic example for a quadratic equation $$ax^2+bx+c=0$$) 1. Write down the quadratic equation. 2. Calculate the discriminant $$\Delta = b^2 - 4ac$$. 3. If $$\Delta > 0$$, two real solutions exist: $$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$$ $$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$$ 4. If $$\Delta = 0$$, one real solution exists: $$x = \frac{-b}{2a}$$ 5. If $$\Delta < 0$$, no real solutions exist. 6. **Explanation:** The discriminant tells us the nature of the roots. Positive means two distinct real roots, zero means one real root (a repeated root), and negative means complex roots. 7. **Final Answer:** The solutions depend on the discriminant and are given by the quadratic formula above.