1. The problem appears to involve solving an equation related to the expression $4 + 12 \cdot 4 + = 5c$ and some steps involving $x$ and $c$. 2. From the notes, it seems you are trying to solve for $x$ in the equation $\frac{5c}{4} = x$ and then use $3x$ and $4x$ in some calculations. 3. Let's clarify and rewrite the problem step-by-step: 4. Suppose the equation is $4 + 12 \cdot 4 + = 5c$, which is unclear. Instead, focus on the equation $\frac{5c}{4} = x$ given. 5. You also have $1:3 x + 3x = 5c$, which can be interpreted as $\frac{1}{3}x + 3x = 5c$. 6. Combine like terms: $$\frac{1}{3}x + 3x = \frac{1}{3}x + \frac{9}{3}x = \frac{10}{3}x = 5c$$ 7. Solve for $x$: $$x = \frac{5c}{\frac{10}{3}} = 5c \times \frac{3}{10} = \frac{15c}{10} = \frac{3c}{2}$$ 8. Check if this matches your $x = \frac{5c}{4}$; it does not, so you need to fix the initial equation or clarify the problem. 9. If you want to use $x = \frac{5c}{4}$, then substitute back into $\frac{1}{3}x + 3x$: $$\frac{1}{3} \times \frac{5c}{4} + 3 \times \frac{5c}{4} = \frac{5c}{12} + \frac{15c}{4} = \frac{5c}{12} + \frac{45c}{12} = \frac{50c}{12} = \frac{25c}{6}$$ 10. This does not equal $5c$, so the equation is inconsistent. 11. To fix your work, clearly define the original equation and carefully combine like terms and solve for $x$ step-by-step. 12. Avoid mixing unrelated expressions and write each step clearly. 13. If you provide the exact original problem, I can help you solve it correctly.