1. The problem states that Angelia's savings account amount is given by the expression $$148.02(1.04)^{t-10}$$ where $t$ is the number of years since the account was opened. 2. We want to find an equivalent expression to $$148.02(1.04)^{t-10}$$. 3. Recall the exponent rule: $$a^{m-n} = \frac{a^m}{a^n}$$. Applying this to our expression: $$148.02(1.04)^{t-10} = 148.02 \times \frac{(1.04)^t}{(1.04)^{10}}$$ 4. Calculate $(1.04)^{10}$: $$ (1.04)^{10} \approx 1.48024 $$ 5. Substitute back: $$148.02 \times \frac{(1.04)^t}{1.48024}$$ 6. Simplify the coefficient: $$\frac{148.02}{1.48024} \approx 100$$ 7. So the expression becomes: $$100(1.04)^t$$ 8. This matches option C. **Final answer:** Option C: $$100(1.04)^t$$