1. **State the problem:** Harry converted 560 pounds to euros in February, then converted his remaining euros back to 120 pounds in April. We need to find how many euros he spent on holiday, rounding to the nearest 10 euros. 2. **Understand the exchange rates:** The problem provides two exchange rate lines (February and April) relating pounds (£) to euros (€). We interpret these as linear functions: - February: Pounds to euros conversion. - April: Euros to pounds conversion. 3. **Find the February exchange rate:** From the graph data points: - At £0, €30 - At £20, €0 This suggests a linear relation: euros = m * pounds + c. Calculate slope $m$: $$m = \frac{0 - 30}{20 - 0} = \frac{-30}{20} = -1.5$$ Intercept $c = 30$ euros. So February conversion formula: $$\text{euros} = -1.5 \times \text{pounds} + 30$$ 4. **Calculate euros received for £560 in February:** Since the graph is for pounds up to 20, we scale accordingly. The rate is linear, so the ratio of euros per pound is: At £0, €30 and at £20, €0 means the euro amount decreases by 1.5 euros per pound. So for £560: $$\text{euros} = 30 - 1.5 \times 560 = 30 - 840 = -810$$ Negative euros don't make sense, so the graph likely shows a different interpretation: the graph shows euros on vertical axis and pounds on horizontal axis, with two lines crossing from (0,30) to (20,0) for February. This means 0 pounds = 30 euros, 20 pounds = 0 euros, so the exchange rate is: $$\text{euros} = 30 - 1.5 \times \text{pounds}$$ But this is for pounds between 0 and 20 only, so for £560, the rate is constant or different. Alternatively, the problem likely means the exchange rate is: - February: £1 = 1.5 euros (since 20 pounds = 0 euros, 0 pounds = 30 euros, the slope is negative, so the rate is 1.5 euros per pound) - April: The reverse rate. 5. **Calculate euros Harry got in February:** Using the rate £1 = 1.5 euros: $$\text{euros} = 560 \times 1.5 = 840$$ 6. **Find the April exchange rate:** From the graph data points for April: - At €0, £0 - At €30, £20 Calculate slope $m$: $$m = \frac{20 - 0}{30 - 0} = \frac{20}{30} = \frac{2}{3}$$ So April conversion formula: $$\text{pounds} = \frac{2}{3} \times \text{euros}$$ 7. **Calculate euros left after holiday:** Harry converted remaining euros to £120 in April: $$120 = \frac{2}{3} \times \text{euros left}$$ Solve for euros left: $$\text{euros left} = \frac{120 \times 3}{2} = 180$$ 8. **Calculate euros spent:** $$\text{euros spent} = \text{euros initially} - \text{euros left} = 840 - 180 = 660$$ 9. **Round to nearest 10 euros:** $$\boxed{660}$$ euros Final answer: Harry spent approximately 660 euros on holiday.