1. **State the problem:** Evaluate the function $f(x) = x^3 - 4x^2 - 11x + 30$ at $x = -3$. 2. **Recall the formula:** To find $f(-3)$, substitute $x$ with $-3$ in the function. 3. **Substitute and calculate:** $$f(-3) = (-3)^3 - 4(-3)^2 - 11(-3) + 30$$ 4. **Simplify powers:** $$= -27 - 4(9) + 33 + 30$$ 5. **Multiply:** $$= -27 - 36 + 33 + 30$$ 6. **Add and subtract step-by-step:** $$-27 - 36 = -63$$ $$-63 + 33 = -30$$ $$-30 + 30 = 0$$ 7. **Final answer:** $$f(-3) = 0$$ So, when $x = -3$, $f(x) = 0$. This means the function value at $x = -3$ is 0.