1. **Problem 1: Evaluate $\frac{3ac}{b}$ given $a=4$, $b=-2$, and $c=-3$.** 2. Use the formula: $$\frac{3ac}{b}$$ 3. Substitute the values: $$\frac{3 \times 4 \times (-3)}{-2} = \frac{3 \times 4 \times (-3)}{-2}$$ 4. Calculate the numerator: $$3 \times 4 = 12$$ $$12 \times (-3) = -36$$ 5. So the expression becomes: $$\frac{-36}{-2}$$ 6. Simplify the fraction by canceling common factors: $$\frac{\cancel{-36}}{\cancel{-2}} = 18$$ 7. The value is $18$. --- Since the first question is solved, we stop here as per instructions.