1. The problem is to evaluate the expression $6e + 15$ where $e$ is the mathematical constant approximately equal to 2.71828. 2. Recall that $e$ is the base of the natural logarithm and is an irrational number. 3. Substitute the approximate value of $e$ into the expression: $$6e + 15 \approx 6 \times 2.71828 + 15$$ 4. Multiply: $$6 \times 2.71828 = 16.30968$$ 5. Add 15: $$16.30968 + 15 = 31.30968$$ 6. Therefore, the value of $6e + 15$ is approximately $31.31$ when rounded to two decimal places.