1. **State the problem:** Evaluate the expression $3 \times (-3)^2 \times 10^0$. 2. **Recall the rules:** - Any number raised to the power of 0 is 1, so $10^0 = 1$. - When squaring a negative number inside parentheses, square the entire number: $(-3)^2 = (-3) \times (-3)$. 3. **Calculate each part:** - Calculate $(-3)^2$: $$(-3)^2 = (-3) \times (-3) = 9$$ - Calculate $10^0$: $$10^0 = 1$$ 4. **Substitute back into the expression:** $$3 \times 9 \times 1$$ 5. **Multiply step-by-step:** $$3 \times 9 = 27$$ $$27 \times 1 = 27$$ 6. **Final answer:** $$\boxed{27}$$