1. The problem asks to find the value of the function $a(x) = 4x^2 + 2x - 5$ at $x = -2$.
2. To solve this, substitute $x = -2$ into the function:
$$a(-2) = 4(-2)^2 + 2(-2) - 5$$
3. Calculate each term step-by-step:
$$4(-2)^2 = 4 \times 4 = 16$$
$$2(-2) = -4$$
4. Now substitute these values back:
$$a(-2) = 16 - 4 - 5$$
5. Simplify the expression:
$$16 - 4 - 5 = 12 - 5 = 7$$
6. Therefore, the value of $a(-2)$ is $7$.
Evaluate Function 226Dc1
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