1. Given the function $f(x) = \frac{2}{3} \cdot 3^{3x + 12}$, evaluate it at $x = -1$. 2. Substitute $x = -1$ into the exponent: $3(-1) + 12 = -3 + 12 = 9$. 3. So, $f(-1) = \frac{2}{3} \cdot 3^9$. 4. Calculate $3^9 = 19683$. 5. Multiply: $f(-1) = \frac{2}{3} \cdot 19683 = \frac{2 \cdot 19683}{3}$. 6. Simplify the fraction: $\frac{2 \cdot \cancel{19683}}{\cancel{3}} = 2 \cdot 6561 = 13122$. Final answer: $f(-1) = 13122$.