1. The problem is to evaluate the function $f(x) = 2 - 3x$ at $x = \frac{1}{2}$. 2. The formula given is $f(x) = 2 - 3x$. To find $f\left(\frac{1}{2}\right)$, substitute $x$ with $\frac{1}{2}$. 3. Substitute: $$f\left(\frac{1}{2}\right) = 2 - 3\left(\frac{1}{2}\right)$$ 4. Multiply: $$3 \times \frac{1}{2} = \frac{3}{2}$$ so $$f\left(\frac{1}{2}\right) = 2 - \frac{3}{2}$$ 5. Convert 2 to a fraction with denominator 2: $$2 = \frac{4}{2}$$ 6. Subtract the fractions: $$\frac{4}{2} - \frac{3}{2} = \frac{4 - 3}{2} = \frac{1}{2}$$ 7. Therefore, the value of the function at $x = \frac{1}{2}$ is $$f\left(\frac{1}{2}\right) = \frac{1}{2}$$.