1. **State the problem:** We need to evaluate the function $g(x) = x^2 + x - 12$ at $x = -4$.
2. **Substitute $x = -4$ into $g(x)$:**
$$g(-4) = (-4)^2 + (-4) - 12$$
3. **Calculate each term:**
$$(-4)^2 = 16$$
$$-4 = -4$$
4. **Sum the terms:**
$$16 + (-4) - 12 = 16 - 4 - 12$$
$$= 0$$
5. **Final answer:**
$$g(-4) = 0$$
Evaluate G
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