1. The problem asks to evaluate the function $g(x)$ at $x = -1$. 2. The function $g(x)$ is defined piecewise as: $$g(x) = \begin{cases} \frac{1}{2}x & \text{if } x < 0 \\ 3 - x & \text{if } 0 \leq x \leq 3 \\ \sqrt{x} & \text{if } x > 3 \end{cases}$$ 3. Since $-1 < 0$, we use the first case: $g(x) = \frac{1}{2}x$. 4. Substitute $x = -1$ into the expression: $$g(-1) = \frac{1}{2} \times (-1) = -\frac{1}{2}$$ 5. Therefore, the value of $g(-1)$ is $-\frac{1}{2}$. 6. In plain language: because $-1$ is less than zero, we use the first formula for $g(x)$, which is half of $x$. Half of $-1$ is $-0.5$, so $g(-1) = -0.5$.