1. **Stating the problem:** We are given the linear function $$y = 18 - 4x$$ and asked to find the value of $$y$$ when $$x = \frac{48}{13}$$. 2. **Formula used:** The function is already given as $$y = 18 - 4x$$. To find $$y$$ for a specific $$x$$, substitute the value of $$x$$ into the equation. 3. **Substitution:** Substitute $$x = \frac{48}{13}$$ into the equation: $$y = 18 - 4 \times \frac{48}{13}$$ 4. **Multiplication:** Calculate $$4 \times \frac{48}{13}$$: $$4 \times \frac{48}{13} = \frac{192}{13}$$ 5. **Rewrite the equation:** $$y = 18 - \frac{192}{13}$$ 6. **Convert 18 to a fraction with denominator 13:** $$18 = \frac{18 \times 13}{13} = \frac{234}{13}$$ 7. **Subtraction of fractions:** $$y = \frac{234}{13} - \frac{192}{13} = \frac{234 - 192}{13} = \frac{42}{13}$$ 8. **Final answer:** $$y = \frac{42}{13}$$ This means when $$x = \frac{48}{13}$$, the value of $$y$$ is $$\frac{42}{13}$$.