Subjects algebra

Evaluate N Expression A362E5

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1. **State the problem:** We are given the expression $$n=\frac{(N-1)E^2+Z^2s^2}{N\cdot Z^2\cdot s^2}$$ with values $$N=4999, E=1, Z=1.7507, s=8.9346$$ and need to evaluate $n$. 2. **Write the formula:** $$n=\frac{(N-1)E^2+Z^2s^2}{N\cdot Z^2\cdot s^2}$$ 3. **Substitute the values:** $$n=\frac{(4999-1)\times 1^2 + (1.7507)^2 \times (8.9346)^2}{4999 \times (1.7507)^2 \times (8.9346)^2}$$ 4. **Calculate numerator parts:** - Calculate $4999-1=4998$ - Calculate $1^2=1$ - Calculate $(1.7507)^2 = 3.06495$ (approx) - Calculate $(8.9346)^2 = 79.812$ (approx) - Calculate $Z^2 s^2 = 3.06495 \times 79.812 = 244.59$ (approx) - Numerator = $4998 \times 1 + 244.59 = 4998 + 244.59 = 5242.59$ 5. **Calculate denominator:** $$4999 \times 3.06495 \times 79.812 = 4999 \times 244.59 = 1,222,875.41$$ (approx) 6. **Form the fraction:** $$n = \frac{5242.59}{1,222,875.41}$$ 7. **Simplify fraction by dividing numerator and denominator by numerator:** $$n = \frac{\cancel{5242.59}}{\frac{1,222,875.41}{5242.59} \times \cancel{5242.59}} = \frac{1}{233.33}$$ (approx) 8. **Final answer:** $$n \approx 0.00429$$ This means the value of $n$ is approximately 0.00429.