1. **State the problem:**
We need to evaluate the expression
$$N' = \left[ \frac{k}{s} \sqrt{N \sum X^2 - (\sum X)^2} \over \sum X \right]^2$$
with the given values:
$$k=2, \quad s=0.05, \quad N=5, \quad \sum X^2=16788.5, \quad (\sum X)^2=83621, \quad \sum X=289.$$
2. **Write the formula clearly:**
$$N' = \left[ \frac{k}{s} \cdot \frac{\sqrt{N \sum X^2 - (\sum X)^2}}{\sum X} \right]^2$$
3. **Calculate the numerator inside the square root:**
$$N \sum X^2 - (\sum X)^2 = 5 \times 16788.5 - 83621 = 83942.5 - 83621 = 321.5$$
4. **Calculate the square root:**
$$\sqrt{321.5} \approx 17.93$$
5. **Calculate the fraction inside the brackets:**
$$\frac{k}{s} = \frac{2}{0.05} = 40$$
6. **Calculate the entire fraction inside the brackets:**
$$\frac{40 \times 17.93}{289} = \frac{717.2}{289} \approx 2.48$$
7. **Square the result:**
$$N' = (2.48)^2 = 6.15$$
**Final answer:**
$$\boxed{6.15}$$
Evaluate N Prime 1F18Ef
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