1. The problem asks to evaluate $f(3)$ for the given step function. 2. A step function is constant on intervals and changes value at specific points. The value at a point depends on whether the circle is open or closed. 3. From the graph description: - For $0 \leq x < 2$, $f(x) = 3$ (closed circle at $x=0$, open at $x=2$) - For $2 \leq x < 4$, $f(x) = 7$ (closed circle at $x=2$, open at $x=4$) - For $4 \leq x < 8$, $f(x) = 11$ - For $8 \leq x < 12$, $f(x) = 14$ 4. Since $3$ is in the interval $2 \leq x < 4$, the function value is $f(3) = 7$. 5. Therefore, the value of the function at $x=3$ is $7$.