Subjects algebra

Exact Value Ab536C

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1. **State the problem:** Calculate the exact value of (i) $\frac{2.8 + 1.36}{4 - 2.7}$ (ii) $\left(\frac{27}{8}\right)^{\frac{1}{3}}$ 2. **Formula and rules:** - For division and addition/subtraction, perform operations in numerator and denominator separately before dividing. - For fractional exponents, $a^{\frac{1}{n}}$ means the $n$th root of $a$. 3. **Calculate (i):** - Numerator: $2.8 + 1.36 = 4.16$ - Denominator: $4 - 2.7 = 1.3$ - Division: $\frac{4.16}{1.3}$ 4. **Simplify (i):** - Multiply numerator and denominator by 10 to clear decimals: $\frac{41.6}{13}$ - Divide: $41.6 \div 13 = 3.2$ 5. **Calculate (ii):** - $\left(\frac{27}{8}\right)^{\frac{1}{3}} = \frac{27^{\frac{1}{3}}}{8^{\frac{1}{3}}}$ - Cube root of 27 is 3, cube root of 8 is 2 - So, $\frac{3}{2} = 1.5$ **Final answers:** (i) $3.2$ (ii) $\frac{3}{2}$ or $1.5$