1. **State the problem:** Simplify and expand the expression $$(3\sqrt{x} - 3)^2$$.
2. **Formula used:** The square of a binomial $$(a - b)^2 = a^2 - 2ab + b^2$$.
3. **Identify terms:** Here, $a = 3\sqrt{x}$ and $b = 3$.
4. **Apply the formula:**
$$
(3\sqrt{x} - 3)^2 = (3\sqrt{x})^2 - 2 \times 3\sqrt{x} \times 3 + 3^2
$$
5. **Calculate each term:**
- $$(3\sqrt{x})^2 = 9x$$
- $$-2 \times 3\sqrt{x} \times 3 = -18\sqrt{x}$$
- $$3^2 = 9$$
6. **Combine all terms:**
$$
9x - 18\sqrt{x} + 9
$$
7. **Final answer:**
$$(3\sqrt{x} - 3)^2 = 9x - 18\sqrt{x} + 9$$
Expand Binomial D642Da
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