1. **State the problem:** Given the equation $$\frac{2^x}{2^y} = 2^3$$, find the value of $x$ in terms of $y$. 2. **Recall the exponent rule:** When dividing powers with the same base, subtract the exponents: $$\frac{a^m}{a^n} = a^{m-n}$$ 3. **Apply the rule to the problem:** $$\frac{2^x}{2^y} = 2^{x-y}$$ 4. **Set the exponents equal since bases are the same:** $$2^{x-y} = 2^3 \implies x - y = 3$$ 5. **Solve for $x$:** $$x = y + 3$$ **Final answer:** $x = y + 3$ which corresponds to option A.