1. **Stating the problem:** Simplify the expression $$\frac{x^{\frac{2}{3}}}{x^{\frac{1}{3}}}$$ and express it in the form $$x^a$$. 2. **Formula used:** When dividing powers with the same base, subtract the exponents: $$\frac{x^m}{x^n} = x^{m-n}$$ 3. **Apply the formula:** $$\frac{x^{\frac{2}{3}}}{x^{\frac{1}{3}}} = x^{\frac{2}{3} - \frac{1}{3}}$$ 4. **Simplify the exponent:** $$\frac{2}{3} - \frac{1}{3} = \frac{2-1}{3} = \frac{1}{3}$$ 5. **Final answer:** $$x^{\frac{1}{3}}$$ This means the simplified form of the given expression is $$x^{\frac{1}{3}}$$, which is the cube root of $$x$$.