1. **State the problem:** Simplify the expression using exponent laws. The expression appears to be $\frac{4a^1 g h x - 3^{2} 2^{2} 2}{6^{9} 2^{h} 2} \times x g h x$. 2. **Rewrite the expression clearly:** $$\frac{4 a^{1} g h x - 3^{2} \cdot 2^{2} \cdot 2}{6^{9} \cdot 2^{h} \cdot 2} \times x g h x$$ 3. **Simplify constants and powers:** - Calculate powers: $3^{2} = 9$, $2^{2} = 4$. - Multiply constants in numerator: $9 \times 4 \times 2 = 72$. - So numerator becomes $4 a g h x - 72$. 4. **Simplify denominator:** - Combine powers of 2: $2^{h} \times 2 = 2^{h+1}$. - So denominator is $6^{9} \times 2^{h+1}$. 5. **Rewrite the expression:** $$\frac{4 a g h x - 72}{6^{9} 2^{h+1}} \times x g h x$$ 6. **Multiply by $x g h x$:** - Combine like terms: $x \times x = x^{2}$. - So multiplication is $x^{2} g h$. 7. **Full expression:** $$\frac{4 a g h x - 72}{6^{9} 2^{h+1}} \times x^{2} g h = \frac{(4 a g h x - 72) x^{2} g h}{6^{9} 2^{h+1}}$$ 8. **Factor numerator:** - Factor out 4: $4 (a g h x - 18)$. 9. **Final simplified form:** $$\frac{4 (a g h x - 18) x^{2} g h}{6^{9} 2^{h+1}}$$ This is the simplified expression using exponent laws and factoring. **Answer:** $$\boxed{\frac{4 (a g h x - 18) x^{2} g h}{6^{9} 2^{h+1}}}$$