1. The problem asks to write $n^4 \cdot n^2$ without exponents and then express it as $n^\square$. 2. Recall the rule for multiplying powers with the same base: $$a^m \cdot a^n = a^{m+n}$$ 3. Applying this rule to $n^4 \cdot n^2$, we add the exponents: $$n^{4+2} = n^6$$ 4. Writing $n^4 \cdot n^2$ without exponents means expanding it as: $$n \cdot n \cdot n \cdot n \cdot n \cdot n$$ 5. So, the expression without exponents is $n$ multiplied by itself 6 times. 6. The final answer is: $$n^4 \cdot n^2 = n^6$$