1. **State the problem:** Simplify the expression $\frac{(q r p^{-2})^{-2} p^{-2} q^{5} r^{0}}{q r}$.\n\n2. **Recall exponent rules:**\n- $(a^m)^n = a^{m \cdot n}$\n- $a^{-m} = \frac{1}{a^m}$\n- $a^0 = 1$ for any $a \neq 0$\n- When multiplying like bases, add exponents: $a^m \cdot a^n = a^{m+n}$\n- When dividing like bases, subtract exponents: $\frac{a^m}{a^n} = a^{m-n}$\n\n3. **Simplify inside the numerator:**\nStart with $(q r p^{-2})^{-2}$. Apply the power of a product rule:\n$$ (q r p^{-2})^{-2} = q^{-2} r^{-2} p^{4} $$\n\n4. **Rewrite numerator:**\n$$ q^{-2} r^{-2} p^{4} \cdot p^{-2} \cdot q^{5} \cdot r^{0} $$\nSince $r^{0} = 1$, it can be omitted:\n$$ q^{-2} r^{-2} p^{4} p^{-2} q^{5} $$\n\n5. **Combine like bases in numerator:**\n$$ q^{-2 + 5} r^{-2} p^{4 - 2} = q^{3} r^{-2} p^{2} $$\n\n6. **Rewrite the entire expression:**\n$$ \frac{q^{3} r^{-2} p^{2}}{q^{1} r^{1}} $$\n\n7. **Divide like bases by subtracting exponents:**\n$$ q^{3 - 1} r^{-2 - 1} p^{2} = q^{2} r^{-3} p^{2} $$\n\n8. **Rewrite negative exponents as fractions:**\n$$ q^{2} p^{2} r^{-3} = \frac{q^{2} p^{2}}{r^{3}} $$\n\n**Final answer:** $$ \frac{p^{2} q^{2}}{r^{3}} $$