Subjects algebra

Exponent Simplification Cac17C

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1. **State the problem:** Simplify the expression $19.88^{-2022} \times 10^{2025}$. 2. **Recall the rules:** When multiplying powers with different bases, you cannot combine the exponents directly unless the bases are the same. 3. **Rewrite the expression:** $$19.88^{-2022} \times 10^{2025} = \frac{10^{2025}}{19.88^{2022}}$$ 4. **Approximate the base ratio:** Since $19.88$ is close to $20$, rewrite $19.88$ as $20 \times \frac{19.88}{20} = 20 \times 0.994$. 5. **Express denominator:** $$19.88^{2022} = (20 \times 0.994)^{2022} = 20^{2022} \times 0.994^{2022}$$ 6. **Rewrite the entire expression:** $$\frac{10^{2025}}{20^{2022} \times 0.994^{2022}} = \frac{10^{2025}}{20^{2022}} \times \frac{1}{0.994^{2022}}$$ 7. **Express $20^{2022}$ in terms of $10$:** $$20 = 2 \times 10 \Rightarrow 20^{2022} = (2 \times 10)^{2022} = 2^{2022} \times 10^{2022}$$ 8. **Substitute back:** $$\frac{10^{2025}}{2^{2022} \times 10^{2022}} \times \frac{1}{0.994^{2022}} = \frac{10^{2025-2022}}{2^{2022}} \times \frac{1}{0.994^{2022}} = \frac{10^{3}}{2^{2022} \times 0.994^{2022}}$$ 9. **Simplify numerator:** $$10^{3} = 1000$$ 10. **Combine denominator terms:** $$2^{2022} \times 0.994^{2022} = (2 \times 0.994)^{2022} = 1.988^{2022}$$ 11. **Final expression:** $$\frac{1000}{1.988^{2022}}$$ 12. **Interpretation:** Since $1.988$ is close to $2$, $1.988^{2022}$ is a very large number, so the entire expression is approximately $\frac{1000}{\text{very large number}}$, which is very close to zero. **Final answer:** $$19.88^{-2022} \times 10^{2025} \approx 0$$