1. The problem is to understand how the equation transitions from the third to the fourth row in the given steps. 2. The third row is: $$2e^{\frac{1}{2}p + 1} - 2e^1 = 2e$$ 3. We can rewrite $$e^{\frac{1}{2}p + 1}$$ as $$e^1 \cdot e^{\frac{1}{2}p}$$ using the property of exponents $$e^{a+b} = e^a \cdot e^b$$. 4. Substitute this into the third row: $$2 \cdot e^1 \cdot e^{\frac{1}{2}p} - 2e^1 = 2e$$ 5. Factor out $$2e^1$$ from the left side: $$2e^1 \left(e^{\frac{1}{2}p} - 1\right) = 2e$$ 6. Since $$e^1 = e$$, rewrite: $$2e \left(e^{\frac{1}{2}p} - 1\right) = 2e$$ 7. Divide both sides by $$2e$$ (showing cancellation): $$\frac{2e \left(e^{\frac{1}{2}p} - 1\right)}{\cancel{2e}} = \frac{2e}{\cancel{2e}}$$ $$e^{\frac{1}{2}p} - 1 = 1$$ 8. Add 1 to both sides: $$e^{\frac{1}{2}p} = 2$$ This matches the fourth row. Hence, the key step is factoring and dividing both sides by $$2e$$ to isolate $$e^{\frac{1}{2}p}$$. Final answer: $$e^{\frac{1}{2}p} = 2$$