1. **State the problem:** Solve the exponential equation $$37^{-4x} + 16 = 41$$ for $x$ and approximate the result to three decimal places.
2. **Isolate the exponential term:** Subtract 16 from both sides:
$$37^{-4x} = 41 - 16$$
$$37^{-4x} = 25$$
3. **Rewrite the equation:** The equation is now:
$$37^{-4x} = 25$$
4. **Take the natural logarithm of both sides:**
$$\ln\left(37^{-4x}\right) = \ln(25)$$
5. **Use the logarithm power rule:**
$$-4x \ln(37) = \ln(25)$$
6. **Solve for $x$:**
$$x = \frac{-\ln(25)}{4 \ln(37)}$$
7. **Calculate the values:**
$$\ln(25) \approx 3.2189$$
$$\ln(37) \approx 3.6109$$
8. **Substitute and simplify:**
$$x = \frac{-3.2189}{4 \times 3.6109} = \frac{-3.2189}{14.4436} \approx -0.223$$
**Final answer:**
$$x \approx -0.223$$
Exponential Equation 0B0Cea
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.