1. **State the problem:** We are given two points on the graph of an exponential function: (1, 24) and (2, 144). We need to find the function of the form $$f(x) = a b^x$$ where $a$ and $b$ are constants.
2. **Formula and rules:** The general form of an exponential function is $$f(x) = a b^x$$ where $a$ is the initial value (when $x=0$) and $b$ is the base or growth factor.
3. **Use the points to form equations:**
- Using point (1, 24): $$f(1) = a b^1 = a b = 24$$
- Using point (2, 144): $$f(2) = a b^2 = 144$$
4. **Divide the second equation by the first to eliminate $a$:**
$$\frac{a b^2}{a b} = \frac{144}{24}$$
$$\cancel{a} b^{2-1} / \cancel{a} = 6$$
$$b = 6$$
5. **Substitute $b=6$ back into the first equation:**
$$a \times 6 = 24$$
$$a = \frac{24}{6}$$
$$a = 4$$
6. **Write the function:**
$$f(x) = 4 \times 6^x$$
7. **Check the options:** The function matches option: $$f(x) = 4(6)^x$$
**Final answer:** $$f(x) = 4(6)^x$$
Exponential Function 58564A
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