1. Let's start by stating the problem: Determine if the function $K(x) = \frac{5^x}{\sqrt{3} \cdot 6^x}$ is exponential. 2. Recall that an exponential function has the form $K(x) = a b^x$, where $a$ and $b$ are constants, and $b > 0$, $b \neq 1$. 3. Rewrite the given function to see if it fits this form: $$K(x) = \frac{5^x}{\sqrt{3} \cdot 6^x} = \frac{1}{\sqrt{3}} \cdot \frac{5^x}{6^x}$$ 4. Use the property of exponents $\frac{a^x}{b^x} = \left(\frac{a}{b}\right)^x$: $$K(x) = \frac{1}{\sqrt{3}} \cdot \left(\frac{5}{6}\right)^x$$ 5. Now, the function is in the form $K(x) = a b^x$ with: $a = \frac{1}{\sqrt{3}}$ $b = \frac{5}{6}$ 6. Since $a$ and $b$ are constants and $b > 0$, the function is indeed exponential. Final answer: $$K(x) = \frac{1}{\sqrt{3}} \left(\frac{5}{6}\right)^x$$ with $a = \frac{1}{\sqrt{3}}$ and $b = \frac{5}{6}$.