1. The problem asks to find the 20th term of the sequence defined by $T_n = 3^n$. 2. The formula for the $n^{th}$ term of this sequence is $T_n = 3^n$, which means each term is 3 raised to the power of $n$. 3. To find the 20th term, substitute $n=20$ into the formula: $$T_{20} = 3^{20}$$ 4. Calculate $3^{20}$: $$3^{20} = 3^{10} \times 3^{10} = 59049 \times 59049 = 3486784401$$ 5. Therefore, the 20th term of the sequence is $3486784401$. This sequence grows exponentially because each term is multiplied by 3 compared to the previous term.