1. The problem is to identify and understand the function described by the graph, which starts at (1,1) and grows steeply to the right, resembling an exponential growth curve. 2. The general form of an exponential function is $$y = a^x$$ where $a > 0$ and $a \neq 1$. 3. Given the point (1,1) lies on the curve, substitute $x=1$ and $y=1$ into the equation: $$1 = a^1$$ which simplifies to $$a = 1$$. 4. However, $a=1$ would produce a constant function $y=1$, which is not exponential growth. 5. The description suggests the curve is exponential growth starting at (1,1), so the function is likely $$y = a^{x}$$ with $a > 1$ and passing through (1,1). 6. To satisfy $y=1$ at $x=1$, we must have $$a^1 = 1$$, so $a=1$, but this contradicts the growth. 7. Another interpretation is the function is shifted or scaled. For example, $$y = a^{x - h}$$ with a horizontal shift $h$. 8. If the curve passes through (1,1), then $$1 = a^{1 - h}$$ which implies $$a^{1 - h} = 1$$. 9. Since $a^{0} = 1$, this means $$1 - h = 0$$ or $$h = 1$$. 10. So the function could be $$y = a^{x - 1}$$. 11. At $x=0$, $$y = a^{-1} = \frac{1}{a}$$, which is less than 1 if $a > 1$, consistent with the curve being to the right of the y-axis and above the x-axis. 12. Therefore, the function is $$y = a^{x - 1}$$ with $a > 1$. Final answer: The function is $$y = a^{x - 1}$$ where $a > 1$ representing exponential growth shifted right by 1 unit.