1. The problem asks which function represents the graph of $f(x) = e^x$ shifted 3 units horizontally to the right. 2. The rule for horizontal shifts is: shifting a function $f(x)$ to the right by $c$ units results in $f(x - c)$. 3. Applying this to $f(x) = e^x$, shifting 3 units right gives: $$g(x) = e^{x - 3}$$ 4. Now, let's analyze the options: - A. $g(x) = e^x + 3$ shifts the graph vertically up by 3 units, not horizontally. - B. $h(x) = e^x - 3$ shifts the graph vertically down by 3 units, not horizontally. - C. $k(x) = e^{x + 3}$ shifts the graph 3 units to the left, not right. - D. $p(x) = e^{x - 3}$ shifts the graph 3 units to the right, which matches our transformation. 5. Therefore, the correct function is $p(x) = e^{x - 3}$. Final answer: D. $p(x) = e^{x - 3}$