1. The problem is to complete the table for the function $y=2^{x-1}$ by calculating the values of $x-1$ and $y$ for each given $x$. 2. The formula is $y=2^{x-1}$. For each $x$, first compute $x-1$, then raise 2 to that power to find $y$. 3. Calculate each row: - For $x=-1$: $x-1 = -1 - 1 = -2$, so $y=2^{-2} = \frac{1}{2^2} = \frac{1}{4} = 0.25$ - For $x=0$: $x-1 = 0 - 1 = -1$, so $y=2^{-1} = \frac{1}{2} = 0.5$ - For $x=1$: $x-1 = 1 - 1 = 0$, so $y=2^0 = 1$ - For $x=2$: $x-1 = 2 - 1 = 1$, so $y=2^1 = 2$ - For $x=3$: $x-1 = 3 - 1 = 2$, so $y=2^2 = 4$ - For $x=4$: $x-1 = 4 - 1 = 3$, so $y=2^3 = 8$ 4. The completed table is: | $x$ | $x-1$ | $y=2^{x-1}$ | |-----|-------|-------------| | -1 | -2 | 0.25 | | 0 | -1 | 0.5 | | 1 | 0 | 1 | | 2 | 1 | 2 | | 3 | 2 | 4 | | 4 | 3 | 8 | 5. The graph of $y=2^{x-1}$ is an exponential curve shifted right by 1 unit compared to $y=2^x$. It passes through $(1,1)$ and increases rapidly for larger $x$, approaching zero but never touching the $x$-axis for smaller $x$.