1. The problem is to find the values of $y = e^x$ for given $x$ values: $-1$, $-\frac{3}{5}$, $-\frac{1}{5}$, $\frac{1}{5}$, $\frac{3}{5}$, and $1$. We are given $y=2.718$ when $x=1$. 2. Recall that $e \approx 2.718$, so $e^1 = e = 2.718$ (given). 3. Calculate each missing $y$ value by evaluating $e^x$: - Box 1: $x = -1$, so $y = e^{-1} = \frac{1}{e} \approx \frac{1}{2.718} \approx 0.368$. - Box 2: $x = -\frac{3}{5} = -0.6$, so $y = e^{-0.6} = \frac{1}{e^{0.6}}$. Using approximation, $e^{0.6} \approx 1.822$, so $y \approx \frac{1}{1.822} \approx 0.549$. - Box 3: $x = -\frac{1}{5} = -0.2$, so $y = e^{-0.2} = \frac{1}{e^{0.2}}$. Since $e^{0.2} \approx 1.221$, $y \approx \frac{1}{1.221} \approx 0.819$. - Box 4: $x = \frac{1}{5} = 0.2$, so $y = e^{0.2} \approx 1.221$. - Box 5: $x = \frac{3}{5} = 0.6$, so $y = e^{0.6} \approx 1.822$. 4. Summary of values: - Box 1 = 0.368 - Box 2 = 0.549 - Box 3 = 0.819 - Box 4 = 1.221 - Box 5 = 1.822 These values complete the table for $y = e^x$ at the specified $x$ values.