1. The problem asks us to find the values of the function $f(x) = 9^x$ for each given $x$ in the table: $-3, -2, -1, 0, 1$. 2. The formula is $f(x) = 9^x$. Important rule: For negative exponents, $a^{-n} = \frac{1}{a^n}$, and for zero exponent, $a^0 = 1$. 3. Calculate each value: - For $x = -3$: $$f(-3) = 9^{-3} = \frac{1}{9^3} = \frac{1}{729}$$ - For $x = -2$: $$f(-2) = 9^{-2} = \frac{1}{9^2} = \frac{1}{81}$$ - For $x = -1$: $$f(-1) = 9^{-1} = \frac{1}{9}$$ - For $x = 0$: $$f(0) = 9^0 = 1$$ - For $x = 1$: $$f(1) = 9^1 = 9$$ 4. Final answers: | x | f(x) | |----|------------| | -3 | $\frac{1}{729}$ | | -2 | $\frac{1}{81}$ | | -1 | $\frac{1}{9}$ | | 0 | $1$ | | 1 | $9$ |