1. **State the problem:** Given the variables and equations: $$B=\frac{A \times 3}{12}$$ $$F=\left(\frac{A}{30 \times 8} \times 0.05 + \frac{A+B}{30 \times 8}\right) \times 52$$ $$H=A+B+F$$ We want to express $H$ in terms of $A$. 2. **Calculate $B$ in terms of $A$:** $$B=\frac{3A}{12}=\frac{A}{4}$$ 3. **Substitute $B$ into $F$:** $$F=\left(\frac{A}{240} \times 0.05 + \frac{A + \frac{A}{4}}{240}\right) \times 52$$ Simplify inside the parentheses: $$\frac{A}{240} \times 0.05 = \frac{0.05A}{240} = \frac{A}{4800}$$ $$A + \frac{A}{4} = \frac{4A}{4} + \frac{A}{4} = \frac{5A}{4}$$ So: $$F=\left(\frac{A}{4800} + \frac{5A}{4 \times 240}\right) \times 52 = \left(\frac{A}{4800} + \frac{5A}{960}\right) \times 52$$ Find common denominator 4800: $$\frac{A}{4800} + \frac{5A}{960} = \frac{A}{4800} + \frac{5A \times 5}{4800} = \frac{A}{4800} + \frac{25A}{4800} = \frac{26A}{4800}$$ 4. **Calculate $F$:** $$F = \frac{26A}{4800} \times 52 = \frac{26 \times 52}{4800} A = \frac{1352}{4800} A = \frac{338}{1200} A = \frac{169}{600} A$$ 5. **Calculate $H$:** $$H = A + B + F = A + \frac{A}{4} + \frac{169}{600} A = \left(1 + \frac{1}{4} + \frac{169}{600}\right) A$$ Convert to common denominator 600: $$1 = \frac{600}{600}, \quad \frac{1}{4} = \frac{150}{600}$$ Sum: $$\frac{600}{600} + \frac{150}{600} + \frac{169}{600} = \frac{919}{600}$$ So: $$H = \frac{919}{600} A$$ **Final answer:** $$H = \frac{919}{600} A$$