1. The problem is to simplify and understand the expression $h \frac{a+b}{2}$ and the term "einangra a" which seems unclear but we focus on the algebraic expression. 2. The expression $h \frac{a+b}{2}$ means $h$ multiplied by the average of $a$ and $b$. 3. The formula used here is the distributive property of multiplication over addition: $$h \times \frac{a+b}{2} = \frac{h(a+b)}{2} = \frac{ha + hb}{2}$$ 4. This means you multiply $h$ by each term inside the parentheses and then divide the sum by 2. 5. So the simplified form is $$\frac{ha + hb}{2}$$ which is the average of $ha$ and $hb$. 6. If you want to factor or rearrange, you can write it as $$\frac{h(a+b)}{2}$$ which is the same expression. 7. This expression is useful in problems involving averages or weighted sums. Final answer: $$h \frac{a+b}{2} = \frac{h(a+b)}{2} = \frac{ha + hb}{2}$$