1. **State the problem:** Calculate the expression $$^n-1r=4(6r^5+2^r+7)$$. 2. **Clarify the expression:** It seems the expression might have a formatting issue. Assuming you want to simplify or evaluate $$4(6r^5 + 2^r + 7)$$ for some value of $r$. The term $$^n-1r$$ is unclear, so we'll focus on simplifying the right side. 3. **Distribute the 4:** Use the distributive property $$a(b+c) = ab + ac$$. $$4(6r^5 + 2^r + 7) = 4 \times 6r^5 + 4 \times 2^r + 4 \times 7$$ 4. **Multiply each term:** $$= 24r^5 + 4 \cdot 2^r + 28$$ 5. **Final simplified expression:** $$24r^5 + 4 \cdot 2^r + 28$$ If you want to evaluate for a specific $r$, substitute the value and calculate. **Summary:** The expression simplifies to $$24r^5 + 4 \cdot 2^r + 28$$.