1. **Stating the problem:** Find three different factor pairs for the numbers 36 and 48. 2. **Formula and rules:** A factor pair of a number $n$ is a pair of integers $(a,b)$ such that $a \times b = n$. 3. **Finding factor pairs for 36:** - Start with 1: $1 \times 36 = 36$ - Next, 2: $2 \times 18 = 36$ - Then, 3: $3 \times 12 = 36$ 4. **Finding factor pairs for 48:** - Start with 1: $1 \times 48 = 48$ - Next, 2: $2 \times 24 = 48$ - Then, 3: $3 \times 16 = 48$ 5. **Explanation:** We chose the smallest factors first because factor pairs are usually listed starting from 1 upwards. Each pair multiplies to the original number, confirming they are valid factor pairs. **Final answer:** - For 36: $(1,36), (2,18), (3,12)$ - For 48: $(1,48), (2,24), (3,16)$