1. **State the problem:** Factor the expression $$27x^3 - 125$$.
2. **Recognize the form:** This is a difference of cubes since $$27x^3 = (3x)^3$$ and $$125 = 5^3$$.
3. **Recall the formula for difference of cubes:**
$$a^3 - b^3 = (a - b)(a^2 + ab + b^2)$$
4. **Identify $$a$$ and $$b$$:**
$$a = 3x$$
$$b = 5$$
5. **Apply the formula:**
$$27x^3 - 125 = (3x - 5)((3x)^2 + (3x)(5) + 5^2)$$
6. **Simplify inside the second parentheses:**
$$= (3x - 5)(9x^2 + 15x + 25)$$
7. **Final factored form:**
$$27x^3 - 125 = (3x - 5)(9x^2 + 15x + 25)$$
Factor Difference Cubes Dcacc7
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