1. **State the problem:** Factor the expression $24n^3 + 68n^2 + 48n$.
2. **Identify the common factors:** Each term contains a factor of $n$, so factor out $n$ first.
3. **Factor out the greatest common factor (GCF):**
$$24n^3 + 68n^2 + 48n = n(24n^2 + 68n + 48)$$
4. **Factor the quadratic inside the parentheses:**
We want to factor $24n^2 + 68n + 48$.
5. **Find the GCF of the quadratic coefficients:** 24, 68, and 48 are all divisible by 4.
6. **Factor out 4:**
$$n(24n^2 + 68n + 48) = n \times 4 (6n^2 + 17n + 12) = 4n(6n^2 + 17n + 12)$$
7. **Factor the quadratic $6n^2 + 17n + 12$:**
We look for two numbers that multiply to $6 \times 12 = 72$ and add to 17.
These numbers are 9 and 8.
8. **Rewrite the middle term:**
$$6n^2 + 9n + 8n + 12$$
9. **Group terms:**
$$(6n^2 + 9n) + (8n + 12)$$
10. **Factor each group:**
$$3n(2n + 3) + 4(2n + 3)$$
11. **Factor out the common binomial:**
$$(3n + 4)(2n + 3)$$
12. **Write the fully factored form:**
$$4n(3n + 4)(2n + 3)$$
**Final answer:** $4n(3n + 4)(2n + 3)$
Factor Polynomial 0A1541
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.