1. **Problem:** Factor the polynomial $x^2 + 11x + 28$. 2. **Formula:** To factor a quadratic $x^2 + bx + c$, find two numbers that multiply to $c$ and add to $b$. 3. **Work:** We need two numbers that multiply to 28 and add to 11. 4. The pairs of factors of 28 are: (1, 28), (2, 14), (4, 7). 5. Among these, 4 and 7 add to 11. 6. So, $x^2 + 11x + 28 = (x + 4)(x + 7)$. 7. **Answer:** $(x + 4)(x + 7)$. This matches answer N from the key. q_count is 15 because there are 15 distinct problems listed, but only the first is solved here as per instructions.