1. The problem is to factor the quadratic expression $x^2 + 6x + 5$. 2. We use the factoring formula for quadratics: $ax^2 + bx + c = (x + m)(x + n)$ where $m$ and $n$ satisfy $m + n = b$ and $mn = c$. 3. Here, $a=1$, $b=6$, and $c=5$. 4. We look for two numbers that add to $6$ and multiply to $5$. These numbers are $1$ and $5$. 5. Therefore, the factorization is $$(x + 1)(x + 5)$$. 6. This means the original quadratic can be expressed as the product of these two binomials.