1. The problem is to factor the quadratic expression $x^2 - x - 6$. 2. The general form of a quadratic expression is $ax^2 + bx + c$. Here, $a=1$, $b=-1$, and $c=-6$. 3. To factor, we look for two numbers that multiply to $c = -6$ and add to $b = -1$. 4. The pairs of factors of $-6$ are $(1, -6)$, $(-1, 6)$, $(2, -3)$, and $(-2, 3)$. 5. Among these, $2 + (-3) = -1$, which matches $b$. 6. Therefore, the factorization is $(x + 2)(x - 3)$. 7. Checking the options, $(x - 3)(x + 2)$ corresponds to option (E). Final answer: (E) $(x - 3)(x + 2)$