1. **State the problem:** Factor the trinomial $9x^2 - 24x + 16$ where the leading coefficient is not 1. 2. **Recall the factoring method:** For a trinomial $ax^2 + bx + c$ where $a \neq 1$, we use the method of finding two numbers that multiply to $a \times c$ and add to $b$. 3. **Calculate:** Here, $a = 9$, $b = -24$, and $c = 16$. Compute $a \times c = 9 \times 16 = 144$. 4. **Find two numbers:** We need two numbers that multiply to 144 and add to -24. These numbers are -12 and -12 because $-12 \times -12 = 144$ and $-12 + (-12) = -24$. 5. **Rewrite the middle term:** Rewrite $-24x$ as $-12x - 12x$: $$9x^2 - 12x - 12x + 16$$ 6. **Group terms:** Group the terms: $$(9x^2 - 12x) + (-12x + 16)$$ 7. **Factor each group:** $$3x(3x - 4) - 4(3x - 4)$$ 8. **Factor out the common binomial:** $$(3x - 4)(3x - 4)$$ 9. **Final answer:** The factorization is $$ (3x - 4)^2 $$