1. The problem is to evaluate the factorial expression $11!$. 2. Recall that the factorial of a positive integer $n$, denoted $n!$, is the product of all positive integers from 1 to $n$: $$n! = n \times (n-1) \times (n-2) \times \cdots \times 2 \times 1$$ 3. For $11!$, this means: $$11! = 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1$$ 4. Calculate step-by-step: $11 \times 10 = 110$ $110 \times 9 = 990$ $990 \times 8 = 7920$ $7920 \times 7 = 55440$ $55440 \times 6 = 332640$ $332640 \times 5 = 1663200$ $1663200 \times 4 = 6652800$ $6652800 \times 3 = 19958400$ $19958400 \times 2 = 39916800$ $39916800 \times 1 = 39916800$ 5. Therefore, the value of $11!$ is: $$\boxed{39916800}$$