1. The problem is to find the result of multiplying all the numbers from 1 to 9, which is called the factorial of 9, denoted as $9!$. 2. The factorial of a positive integer $n$ is defined as the product of all positive integers from 1 to $n$: $$n! = 1 \times 2 \times 3 \times \cdots \times n$$ 3. Applying this to $9!$, we have: $$9! = 1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9$$ 4. Calculate step-by-step: $$1 \times 2 = 2$$ $$2 \times 3 = 6$$ $$6 \times 4 = 24$$ $$24 \times 5 = 120$$ $$120 \times 6 = 720$$ $$720 \times 7 = 5040$$ $$5040 \times 8 = 40320$$ $$40320 \times 9 = 362880$$ 5. Therefore, the value of $9!$ is: $$\boxed{362880}$$