1. **Problem:** Calculate $\frac{10!}{8!}$. 2. **Recall the factorial definition:** $$n! = n \times (n-1) \times (n-2) \times \cdots \times 1$$ 3. **Express $10!$ and $8!$ explicitly:** $$10! = 10 \times 9 \times 8!$$ 4. **Substitute into the expression:** $$\frac{10!}{8!} = \frac{10 \times 9 \times 8!}{8!}$$ 5. **Cancel the common factor $8!$:** $$\frac{10 \times 9 \times \cancel{8!}}{\cancel{8!}} = 10 \times 9$$ 6. **Calculate the product:** $$10 \times 9 = 90$$ 7. **Final answer:** $$\boxed{90}$$ This means $\frac{10!}{8!} = 90$. --- **Note:** The user asked to solve all, but per instructions, only the first problem is solved here.