1. **State the problem:** Evaluate the expression $ (4 + 3)! $ and determine if the result is an integer or not. 2. **Recall the factorial definition:** For any positive integer $n$, $n!$ (n factorial) is the product of all positive integers from 1 to $n$. 3. **Calculate inside the parentheses first:** $$4 + 3 = 7$$ 4. **Apply the factorial:** $$7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1$$ 5. **Calculate step-by-step:** $$7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040$$ 6. **Interpret the result:** The factorial of 7 is 5040, which is an integer. **Final answer:** $$(4 + 3)! = 7! = 5040$$ Therefore, the value is an integer.