1. **State the problem:** Find the value of $$\frac{10! + 9!}{8!}$$ and express your answer as an integer. 2. **Recall factorial definitions:** - $$10! = 10 \times 9 \times 8!$$ - $$9! = 9 \times 8!$$ 3. **Rewrite the numerator using factorial expansions:** $$10! + 9! = (10 \times 9 \times 8!) + (9 \times 8!)$$ 4. **Factor out $$8!$$ from the numerator:** $$10! + 9! = 8! \times (10 \times 9 + 9) = 8! \times (90 + 9) = 8! \times 99$$ 5. **Substitute back into the original expression:** $$\frac{10! + 9!}{8!} = \frac{8! \times 99}{8!}$$ 6. **Cancel $$8!$$ in numerator and denominator:** $$\frac{\cancel{8!} \times 99}{\cancel{8!}} = 99$$ 7. **Final answer:** $$\boxed{99}$$ The value of $$\frac{10! + 9!}{8!}$$ is 99.